How to solve Leetcode 804. Unique Morse Code Words
Morse Code decoding is not unique
Problem statement
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:
'a'
maps to".-"
,'b'
maps to"-..."
,'c'
maps to"-.-."
, and so on.
For convenience, the full table for the 26
letters of the English alphabet is given below:
[".-", "-...", "-.-.", "-..", ".", "..-.", "--.",
"....", "..", ".---", "-.-", ".-..", "--", "-.",
"---", ".--.", "--.-", ".-.", "...", "-", "..-",
"...-", ".--", "-..-", "-.--", "--.."]
Given an array of strings words
where each word can be written as a concatenation of the Morse code of each letter.
- For example,
"cab"
can be written as"-.-..--..."
, which is the concatenation of"-.-."
,".-"
, and"-..."
. We will call such a concatenation the transformation of a word.
Return the number of different transformations among all words we have.
Example 1
Input: words = ["gin","zen","gig","msg"]
Output: 2
Explanation: The transformation of each word is:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."
There are 2 different transformations: "--...-." and "--...--.".
Example 2
Input: words = ["a"]
Output: 1
Constraints
1 <= words.length <= 100
.1 <= words[i].length <= 12
.words[i]
consists of lowercase English letters.
Solution: Store the transformations in a set
Code
#include <iostream>
#include <vector>
#include <unordered_set>
using namespace std;
int uniqueMorseRepresentations(vector<string>& words) {
vector<string> morse{".-", "-...", "-.-.", "-..", ".", "..-.", "--.",
"....", "..", ".---", "-.-", ".-..", "--", "-.",
"---", ".--.", "--.-", ".-.", "...", "-", "..-",
"...-", ".--", "-..-", "-.--", "--.."};
unordered_set<string> transformations;
for (string& w : words) {
string s{""};
for (char& c : w) {
s += morse[c - 'a'];
}
transformations.insert(s);
}
return transformations.size();
}
int main() {
vector<string> words{"gin","zen","gig","msg"};
cout << uniqueMorseRepresentations(words) << endl;
words = {"a"};
cout << uniqueMorseRepresentations(words) << endl;
}
Output:
2
1
Complexity
Runtime:
O(N*M)
, whereN = words.length
andM = words[i].length
.Extra space:
O(N)
.